x^2/5+(12/5)x=-7

Solution for x^2/5+(12/5)x=-7 equation:

x^2/5+(12/5)x=-7

We move all terms to the left:

x^2/5+(12/5)x-(-7)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x^2/5+(+12/5)x-(-7)=0

We add all the numbers together, and all the variables

x^2/5+(+12/5)x+7=0

We multiply parentheses

x^2/5+12x^2+7=0

We multiply all the terms by the denominator


x^2+12x^2*5+7*5=0

We add all the numbers together, and all the variables

x^2+12x^2*5+35=0

Wy multiply elements

x^2+60x^2+35=0

We add all the numbers together, and all the variables

61x^2+35=0

a = 61; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·61·35
Δ = -8540
Delta is less than zero, so there is no solution for the equation